5x^2-64x-50=0

Solution for 5x^2-64x-50=0 equation:

5x^2-64x-50=0

a = 5; b = -64; c = -50;
Δ = b2-4ac
Δ = -642-4·5·(-50)
Δ = 5096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5096}=\sqrt{196*26}=\sqrt{196}*\sqrt{26}=14\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-14\sqrt{26}}{2*5}=\frac{64-14\sqrt{26}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+14\sqrt{26}}{2*5}=\frac{64+14\sqrt{26}}{10}
$